|3x-2|=x+1 (1)
* Nếu 3x-2 ≥ 0
=> x ≥ $\frac{2}{3}$
(1) => 3x-2 =x+1
<=> 3x -x = 1 + 2
<=> 2x = 3
<=> x = $\frac{3}{2}$ (TM)
* Nếu 3x -2 <0
=> x < $\frac{2}{3}$
(1) => -3x+2 = x+1
<=> -3x-x= 1 -2
<=> -4x = -1
<=> x = $\frac{1}{4}$ (TM)
Vậy S = { $\frac{3}{2}$ , $\frac{1}{4}$ }
#number one
#Trang Huyen