Đáp án:
1. a, $\dfrac{1}{3}$ ≤x≤ 1
b, \(\left[ \begin{array}{l}x>4\\x<3\end{array} \right.\)
2. a,pttq: ( x - 1 )² + ( y + 2 )² = 26
b, pttq: ( y + 1 )² + ( x - 2 )² = $\dfrac{1}{25}$
Giải thích các bước giải:
1. a, $\dfrac{1}{3}$ ≤x≤ 1
b, \(\left[ \begin{array}{l}x>4\\x<3\end{array} \right.\)
2. a, R = MI = $\sqrt{26}$
pttq: ( x - 1 )² + ( y + 2 )² = 26
b, R = d(I,Δ) = $\dfrac{|3.2-2-5|}{5} =\dfrac{1}{5}$
pttq: ( y + 1 )² + ( x - 2 )² = $\dfrac{1}{25}$