$29)v(3)=s'(3)=6.3^2+5=59\\ \Rightarrow C\\ 30. B\\ II\\ 1)a)\lim \dfrac{6n^2}{3n^2-1}\\ =\lim \dfrac{6}{3-\dfrac{1}{n^2}}\\ =\dfrac{6}{3}\\ =2\\ b) \displaystyle \lim_{x \to 2} (2x^3-3x^2+2)\\ = 2.2^3-3.2^2+2\\ =6\\ 2)y=f(x)=x^3-5x+4\\ a)y'=3x^2-5\\ b)y'(2)=7\\ Pttt:y=y'(2)(x-2)+y(2)\\ \Leftrightarrow y=7x−12$