Em tham khảo nha:
\(\begin{array}{l}
a)\\
{m_{hh}} = {m_{Fe}} + {m_{Cu}} = 0,2 \times 56 + 0,5 \times 64 = 43,2g\\
b)\\
{n_{C{O_2}}} = \dfrac{{67,2}}{{22,4}} = 3\,mol\\
{n_{CO}} = \dfrac{{11,2}}{{22,4}} = 0,5\,mol\\
{n_{{N_2}}} = \dfrac{{5,6}}{{22,4}} = 0,25\,mol\\
{m_{hh}} = {m_{C{O_2}}} + {m_{CO}} + {m_{{N_2}}}\\
\Rightarrow {m_{hh}} = 3 \times 44 + 0,5 \times 28 + 0,25 \times 28 = 153g
\end{array}\)
