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`B = 4 (a^3 +b^3) - 6 (a^2 + b^2)`
`->B = 4 (a+b)(a^2 - ab + b^2) - 6 (a^2 + b^2)`
`->B = 4 (a^2 - ab+b^2) - 6a^2 - 6b^2`
`->B = 4a^2 - 4ab + 4b^2 - 6a^2 - 6b^2`
`->B = -2a^2 -4ab - 2b^2`
`->B = -2 (a^2 + 2ab + b^2)`
`->B = -2 (a+b)^2`
`->B = -2 . 1` (Do `a+b=1 ->(a+b)^2=1`)
`->B=-2`
Vậy `B=-2` khi `a+b=1`