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khanhduongia
1 năm trước
Giúp e gấp câu này với mn !! g(x)=(f$(3-x))^{2}$ g'(x)=f'(3-x) × [2 ×(3-x) ×(-1)] Cho e hỏi là e dùng phương pháp thử thế x=3 vào g'(x) thì ra đc f'(0) ×(0) Vậy làm sao để biết nó đồng hay nghịch biến ạ , hay cách e làm sai
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