Em tham khảo nha:
\(\begin{array}{l}
2)\\
{m_S}:{m_O} = 16:24 \Leftrightarrow 32x:16y = 16:24\\
\Leftrightarrow \dfrac{{2x}}{y} = \dfrac{2}{3} \Rightarrow \dfrac{x}{y} = \dfrac{1}{3} \Rightarrow CTHH:S{O_3}\\
3)\\
AC{O_3} + 2HCl \to AC{l_2} + C{O_2} + {H_2}O\\
{B_2}C{O_3} + 2HCl \to 2BCl + C{O_2} + {H_2}O\\
{R_2}C{O_3} + 2HCl \to 2RCl + C{O_2} + {H_2}O\\
{n_{C{O_2}}} = \dfrac{{0,448}}{{22,4}} = 0,02\,mol\\
{n_{HCl}} = 2{n_{C{O_2}}} = 0,04\,mol\\
{n_{{H_2}O}} = {n_{C{O_2}}} = 0,02\,mol\\
BTKL:\\
{m_{hh}} + {m_{HCl}} = m + {m_{C{O_2}}} + {m_{{H_2}O}}\\
\Rightarrow m = 115 + 0,04 \times 36,5 - 0,02 \times 44 - 0,02 \times 18 = 115,22g
\end{array}\)
