Gọi:$\left \{ {{n_{ZnO}=x} \atop {n_{Fe_{2}O_{3}}=y}} \right.$
$PTHH:ZnO+CO \xrightarrow {t^o} Zn + CO_{2}$
$mol:$ x → x→ x
$PTHH:Fe_{2}O_{3}+3CO \xrightarrow {t^o} 2Fe+3CO_{2}$
$mol:$ y 2y→ 3y
$m_{hh kim loại}=m_{Zn}+m_{Fe}=23,3(g)$
$⇔65x+112y=23,3(1)$
*Hấp thụ khí vào $Ca(OH)_{2}$:
$n_{CaCO_{3}}=\frac{55}{100}=0,55(mol)$
$PTHH:Ca(OH)_{2}+CO_{2}→CaCO_{3}↓+H_{2}O$
$mol:$ 0,55 ← 0,55
⇒$n_{CO_{2}}=x+3y=0,55(mol)(2)$
Giải hệ $(1)$,$(2)$⇒$\left \{ {{x=0,1} \atop {y=0,15}} \right.$
$m_{ZnO}=0,1.81=8,1(g)$
$m_{Fe_{2}O_{3}}=0,15.160=24(g)$
