Em tham khảo nha:
\(\begin{array}{l}
2)\\
a)\\
{m_{{\rm{ddHN}}{{\rm{O}}_3}}} = V \times D = 50 \times 1,25 = 62,5g\\
b)\\
{m_{HN{O_3}}} = \dfrac{{{m_{{\rm{dd}}}} \times {C_\% }}}{{100}} = \dfrac{{62,5 \times 40}}{{100}} = 25g\\
c)\\
{n_{HN{O_3}}} = \dfrac{m}{M} = \dfrac{{25}}{{63}} \approx 0,4\,mol\\
{C_M}(HN{O_3}) = \dfrac{n}{V} = \dfrac{{0,4}}{{0,05}} = 8(M)\\
3)\\
TH1:\\
{n_{HCl}} = \dfrac{V}{{22,4}} = \dfrac{{26,88}}{{22,4}} = 1,2\,mol\\
{C_M}HCl = \dfrac{n}{V} = \dfrac{{1,2}}{{0,5}} = 2,4(M)\\
TH2:\\
{n_{N{a_2}C{O_3}.10{H_2}O}} = \dfrac{m}{M} = \dfrac{{28,6}}{{286}} = 0,1\,mol\\
{n_{N{a_2}C{O_3}}} = {n_{N{a_2}C{O_3}.10{H_2}O}} = 0,1\,mol\\
{C_M}(N{a_2}C{O_3}) = \dfrac{n}{V} = \dfrac{{0,1}}{{0,2}} = 0,5M
\end{array}\)
