Đáp án: $B$
Giải thích các bước giải:
Ta có:
$P=|\vec{u}+\vec{v}|$
$\to P^2=|\vec{u}+\vec{v}|^2$
$\to P^2=(\vec{u}+\vec{v})^2$
$\to P^2=\vec{u}^2+\vec{v}^2+2\vec{u}\cdot \vec{v}$
$\to P^2=|\vec{u}|^2+|\vec{v}|^2+2|\vec{u}|\cdot|\vec{v}|\cdot \cos(\vec{u},\vec{v})$
$\to P^2=5^2+3^2+2\cdot 5\cdot 3\cdot \cos120^o$
$\to P^2=19$
$\to P=\sqrt{19}$
$\to B$