Đáp án:
$(1) 2NaCl + 2H_{2}O → Cl_{2} + 2NaOH + H_{2}$
$(2) 2KMnO_{4}+ 16HCl → 2KCl + 2MnCl_{2} + 8H_{2}O + 5Cl_{2}$
$(3) MnO_{2} + 4HCl → MnCl_{2} + Cl_{2} + 2H_{2}O$
$(4) 2Fe + 3Cl_{2} → 2FeCl_{3}$
$(5) H_{2} + Cl_{2} → 2HCl$
$(6) H_{2}O + Cl_{2}→ HCl + HClO$
$(7) 3Cl_{2} + 6KOH → 5KCl + KClO_{3} + 3H_{2}O$
$(8) 2NaOH + Cl_{2} → NaClO + NaCl + H_{2}O$
