Đáp án: 1. (x-2)(x-3)=0
⇒ \(\left[ \begin{array}{l}x-2=0\\x-3=0\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=2\\x=3\end{array} \right.\)
2. 2x.(x-1)+3.(x-1)=0
⇔ (x-1).(2x+3) =0
⇒ \(\left[ \begin{array}{l}x-1=0\\2x+3=0\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=1\\x=\frac{-3}{2} \end{array} \right.\)