Đáp án:
\(\begin{array}{l}
2.{V_{{H_2}}} = 7,467l\\
3.{m_{MgS{O_4}}} = 40g\\
4.{m_{{H_2}S{O_4}}} = 32,67g\\
5.{C_\% }MgS{O_4} = 15,54\%
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
1.\,Mg + {H_2}S{O_4} \to MgS{O_4} + {H_2}\\
2.\,\\
{n_{Mg}} = \dfrac{8}{{24}} = \dfrac{1}{3}\,mol\\
{n_{{H_2}}} = {n_{Mg}} = \dfrac{1}{3}\,mol\\
{V_{{H_2}}} = \dfrac{1}{3} \times 22,4 = 7,467l\\
3.\\
{n_{MgS{O_4}}} = {n_{Mg}} = \dfrac{1}{3}\,mol\\
{m_{MgS{O_4}}} = \dfrac{1}{3} \times 120 = 40g\\
4.\\
{n_{{H_2}S{O_4}}} = {n_{Mg}} = \dfrac{1}{3}\,mol\\
{m_{{H_2}S{O_4}}} = \dfrac{1}{3} \times 98 = 32,67g\\
5.\\
{m_{{\rm{dd}}spu}} = 8 + 250 - \frac{1}{3} \times 2 = 257,33g\\
{C_\% }MgS{O_4} = \dfrac{{40}}{{257,33}} \times 100\% = 15,54\%
\end{array}\)
