Đáp án:
\(\begin{array}{l}
a)A = \dfrac{4}{{15}}a{x^3}y\\
B = - \dfrac{3}{2}a{b^3}{x^3}{y^3}\\
C = \dfrac{1}{4}a{b^3}{x^4}{y^6}\\
D = - \dfrac{1}{{10}}{x^2}{y^3}{z^3}\\
E = \dfrac{3}{5}{x^8}{y^6}
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)A = \dfrac{1}{3}.\dfrac{4}{5}.a{x^{1 + 2}}.y = \dfrac{4}{{15}}a{x^3}y\\
B = - \dfrac{3}{4}.2.{b^3}.{x^3}.a.{y^3}\\
= - \dfrac{3}{2}a{b^3}{x^3}{y^3}\\
C = \dfrac{1}{4}.ax.{\left( { - x} \right)^3}.{y^3}.{\left( { - b} \right)^3}.{y^3}\\
= \dfrac{1}{4}a{b^3}{x^4}{y^6}\\
D = - \dfrac{4}{{15}}.\dfrac{3}{8}.{x^{1 + 1}}.{y^{2 + 1}}.{z^3}\\
= - \dfrac{1}{{10}}{x^2}{y^3}{z^3}\\
E = \dfrac{1}{4}.\dfrac{{12}}{5}{x^{6 + 2}}.{y^{2 + 4}}\\
= \dfrac{3}{5}{x^8}{y^6}\\
b)A = \dfrac{4}{{15}}a{x^3}y\\
HS:\dfrac{4}{{15}}a\\
Bậc:3 + 1 = 4\\
B = - \dfrac{3}{2}a{b^3}{x^3}{y^3}\\
HS: - \dfrac{3}{2}a{b^3}\\
Bậc:3 + 3 = 6\\
C = \dfrac{1}{4}a{b^3}{x^4}{y^6}\\
HS:\dfrac{1}{4}a{b^3}\\
Bậc:4 + 6 = 10\\
D = - \dfrac{1}{{10}}{x^2}{y^3}{z^3}\\
HS: - \dfrac{1}{{10}}\\
Bậc:2 + 3 + 3 = 8\\
E = \dfrac{3}{5}{x^8}{y^6}\\
HS:\dfrac{3}{5}\\
Bậc:8 + 6 = 14
\end{array}\)
