`1.`
`Ta` ` có:`
` Vì ` `D<1=>D<`$\frac{10^{2006}+1+9}{10^{2007}+1+9}$ `=`$\frac{10^{2006}+10}{10}$`=`$\frac{10(10^{2005}+1)}{10(10^{2006}1)}$ =$\frac{10^{2005}+1}{10^{2006}1}$`=C`
` Vậy ` `D<C`
` 2.`
`Ta` ` có:`
` Vì N<1=>N<`$\frac{199+1802}{200+1802}$`=`$\frac{2001}{2002}$`=M`
`Vậy` `N<M`
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