Đáp án:
$\dfrac{65}{9}$
Giải thích các bước giải:
$\left ( 3\dfrac{1}{3}.1,9+19,5:4\dfrac{1}{3} \right ).\left ( \dfrac{62}{75}-\dfrac{4}{25} \right )\\=\left ( \dfrac{10}{3}.1,9+19,5.\dfrac{3}{13} \right ).\left ( \dfrac{62}{75}-\dfrac{12}{75} \right )\\=\left ( \dfrac{19}{3}+\dfrac{9}{2} \right ).\dfrac{2}{3}\\=\dfrac{65}{6}.\dfrac{2}{3}=\dfrac{65}{9}$
