`a)(4116-14)/(10290-35)=4102/10225=2/5`
`b)(2929-101)/(2.1919+404)=[101(29-1)]/[101(2.19+4)]=(101.28)/(101.42)=2/3`
`c)(36036-3003)/(46046+2002)=[1001(36-3)]/[1001(46+2)]=(1001.33)/(1001.48)=11/16`
`d)(8^6 .25^5)/(16^5 .125^3)=(2^18 .5^10)/(2^20 .5^9)=5/4`
`e)(9^3 .5-3^6 .2)/(9^4+3^8 .5)=(3^6 .5-3^6 .2)/(3^8+3^8.5)=[3^6(5-2)]/[3^8(1+5)]=(3^6 .3)/(3^8 .6)=1/18`
