d) $\frac{2}{3}$x- $\frac{3}{2}$x+ $\frac{3}{4}$= $\frac{5}{12}$
$\frac{2}{3}$x- $\frac{3}{2}$x+ $\frac{3}{4}$= $\frac{5}{12}$
x($\frac{2}{3}$- $\frac{3}{2}$)= $\frac{5}{12}$-$\frac{3}{4}$
$\frac{-5}{6}$x=$\frac{-1}{3}$
x=$\frac{-1}{3}$:$\frac{-5}{6}$
x=$\frac{2}{5}$
Vậy x=$\frac{2}{5}$
