=4sinx.$\frac{cos($\frac{π}{3}$ - x - $\frac{π}{3}$ - x) - cos ( $\frac{π}{3}$ - x + $\frac{π}{3}$ + x )}{2}$
=2sinx.[cos(-2x)-cos$\frac{2π}{3}$ ]
=2sinx.[cos(2x)+1/2]
= 2sinx.( 1- $2sin^{2}x$ +1/2)
= 2sinx.( 3/2 - 2sinx.sinx)
=3sinx - $4sin^{3}x$
=sin3x(đpcm)