a) thế x=9 vào pt A ta đc :
A=$\frac{3+1}{3-1}$
=2
b)
B=($\frac{√x+1}{√x-1}$ -$\frac{√x-1}{√x+1}$ ):$\frac{√x}{√x-1}$
=($\frac{(√x+1)²-(√x-1)²}{x-1}$):$\frac{√x(√x+1)}{x-1}$
=($\frac{(√x+1+√x-1)(√x+1-√x+1)}{x-1}$).$\frac{x-1}{√x(√x+1)}$
=$\frac{4√x}{x-1}$.$\frac{x-1}{√x(√x+1)}$
=$\frac{4}{√x+1}$
c)