Đáp án:
Xin hay nhất ạ :)
Giải thích các bước giải:
a. $(x-1)^{2}=0$
$=>x-1=0$
$=>x=0+1$
$=>x=1$
b. $x(x-1)=0$
\(=>\left[ \begin{array}{l}x=0\\x-1=0\end{array} \right.\)
\(=>\left[ \begin{array}{l}x=0\\x=0+1\end{array} \right.\)
\(=>\left[ \begin{array}{l}x=0\\x=1\end{array} \right.\)
c. $(x +1)(x-2)=0$
\(=>\left[ \begin{array}{l}x+1=0\\x-2=0\end{array} \right.\)
\(=>\left[ \begin{array}{l}x=0-1\\x=0+2\end{array} \right.\)
\(=>\left[ \begin{array}{l}x=-1\\x=2\end{array} \right.\)
d. $x(x+2)(x-3)=0$
\(=>\left[ \begin{array}{l}x=0\\x+2=0\\x-3=0\end{array} \right.\)
\(=>\left[ \begin{array}{l}x=0\\x=0-2\\x=0+3\end{array} \right.\)
\(=>\left[ \begin{array}{l}x=0\\x=-2\\x=3\end{array} \right.\)
e. $2.(3-6x)+8.(x-5)=-42$
$=>(6-12x)+(8x-40)+42=0$
$=>6-12x+8x-40+42=0$
$=>8-4x=0$
$=>4x=8-0$
$=>4x=8$
$=>x=8:4$
$=>x=2$
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