a, x²+4x =0
x( x+4)=0
⇒x =0 hoặc x+4=0⇔x=-4
c,x²+7x=8
x²+7x-8 =0
x²-x +8x-8=0
x(x-1)+8(x-1)=0
(x-1)(x+8)=0
⇒x-1=0 hoặc x+8 =0 ⇔x=-8
⇒x=1
b,5x.( 3x-2) = 4 - 9x²
5x ( 3x-2) - ( 4- 9x²)= 0
5x ( 3x -2) - [ ( 2 -3x) ( 2+3x) ]=0
5x (3x-2) + ( 3x -2) ( 2+3x) =0
(3x -2) ( 8x+ 2)=0
⇒ từng thừa số = 0