`sin(x-π/3)=cos((5π)/6)`
`<=>sin(x-π/3)=sin(π/2-(5π)/6)`
`<=>sin(x-π/3)=sin((-π)/3)`
`<=>`\(\left[ \begin{array}{l}x-\dfrac{π}{3}=\dfrac{-π}{3}+k2π\\x-\dfrac{π}{3}=π+\dfrac{π}{3}+k2π\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=k2π\\x=\dfrac{5π}{3}+k2π\end{array} \right.\)`(kinZZ)`