Đáp án:
\({m_c} = 0,226kg,{m_t} = 0,438kg\)
Giải thích các bước giải:
\(\begin{array}{l}
m = {m_c} + {m_t} = 664g = 0,664kg(1)\\
V = {V_c} + {V_t}\\
\frac{m}{D} = \frac{{{m_c}}}{{{D_c}}} + \frac{{{m_t}}}{{{D_t}}}\\
\frac{{0,664}}{{\frac{{8,{{3.10}^{ - 3}}}}{{{{10}^{ - 6}}}}}} = \frac{{{m_c}}}{{11300}} + \frac{{{m_t}}}{{7300}}\\
\frac{1}{{12500}} = \frac{{{m_c}}}{{11300}} + \frac{{{m_t}}}{{7300}}(2)\\
(1),(2) \Rightarrow {m_c} = 0,226kg,{m_t} = 0,438kg
\end{array}\)