` A = 5/(1*3) + 5/(3*5) + 5/(5*7) + ... + 5/(99*101)`
` A/5 = ( 1/(1*3) + 1/(3*5) + 1/(5*7) + ... + 1/(99*101)`
` (2/5)A = ( 2/(1*3) + 2/(3*5) + 2/(5*7) + ... + 2/(99*101)`
` (2/5)A = 1 - 1/3 + 1/3 - 1/5 + 1/5 - 1/7 + ... + 1/99 - 1/101`
` (2/5)A= ( 1-1/101 ) `
` (2/5)A= (100/101)`
` A= 250/101`
`#KAITO#`