Đáp án+giải thích các bước giải:
C2:
c)
$|\dfrac{8}{3}x-\dfrac{1}{3}|=\dfrac{3}{4}$
TH1:
$\dfrac{8}{3}x-\dfrac{1}{3}=\dfrac{3}{4}$
$\dfrac{8}{3}x=\dfrac{3}{4}+\dfrac{1}{3}$
$\dfrac{8}{3}x=\dfrac{13}{12}$
$x=\dfrac{13}{12}:\dfrac{8}{3}$
$x=\dfrac{13}{32}$
TH2:
$\dfrac{8}{3}x-\dfrac{1}{3}=\dfrac{-3}{4}$
$\dfrac{8}{3}x=\dfrac{-3}{4}+\dfrac{1}{3}$
$\dfrac{8}{3}x=\dfrac{-5}{12}$
$x=\dfrac{-5}{12}:\dfrac{8}{3}$
$x=\dfrac{-5}{32}$
Vậy $x=\dfrac{13}{32}$ hoặc $x=\dfrac{-5}{32}$
