Đáp án + Giải thích các bước giải:
`e)`
`(2)/(\sqrt{6}-2)+(2)/(\sqrt{6}+2)+(5)/(\sqrt{6})`
`=(2(\sqrt{6}+2)+2(\sqrt{6}-2))/((\sqrt{6}-2)(\sqrt{6}+2))+(5)/(\sqrt{6})`
`=(2(\sqrt{6}+2+\sqrt{6}-2))/(6-4)+(5)/(\sqrt{6})`
`=(2.2\sqrt{6})/(2)+(5)/(\sqrt{6})`
`=2\sqrt{6}+(5)/(\sqrt{6})`
`=(12)/(\sqrt{6})+(5)/(\sqrt{6})`
`=(17)/(\sqrt{6})`
`=(17\sqrt{6})/(6)`
`h)`
`(5)/(\sqrt{7}+\sqrt{2})-\sqrt{8-2\sqrt{7}}+\sqrt{2}`
`=(5(\sqrt{7}-\sqrt{2}))/((\sqrt{7}+\sqrt{2})(\sqrt{7}-\sqrt{2}))-\sqrt{(1-\sqrt{7})^{2}}+\sqrt{2}`
`=(5(\sqrt{7}-\sqrt{2}))/(7-2)-|1-\sqrt{7}|+\sqrt{2}`
`=(5(\sqrt{7}-\sqrt{2}))/(5)-(\sqrt{7}-1)+\sqrt{2}`
`=\sqrt{7}-\sqrt{2}-\sqrt{7}+1+\sqrt{2}`
`=1`
