Giải thích các bước giải:
$HCOOCH_{3}$+$NaOH_{}$→$HCOONa_{}$+$CH_{3}$ $OH_{}$.
$CH_{3}$$COO_{}$ $CH(CH_{3}$ $)_{2}$+ $NaOH_{}$→ $CH_{3}$$COO_{}$$Na_{}$ + $CH_{3}$ $-CH(OH)_{}$ $-CH_{3}$ .
$CH_{2}$ $=C(CH_{3}$ $)COOCH_{3}$+ $NaOH_{}$→$CH_{2}$ $=CH(CH_{3}$ $)COONa_{}$+$CH_{3}$ $OH_{}$.
$C_{6}$ $H_{5}$ $COOCH_{2}$$-CH=CH_{2}$ + $NaOH_{}$→$C_{6}$ $H_{5}$ $COONa_{}$+$CH_{2}$ $=CH-CH_{2}$$-OH_{}$ .
$CH_{3}$ $COOCH=CH_{2}$+ $KOH_{}$→$CH_{3}$$COO_{}$$K_{}$+$CH_{3}$ $CHO_{}$ .
$CH_{3}$ $COOC(_{3}$$)=CH_{2}$ + $KOH_{}$→$CH_{3}$ $COOK_{}$+$CH_{3}$ $COCH_{3}$ .
$HCOOC_{6}$ $H_{5}$+ $KOH_{}$→$HCOONa_{}$+$C_{6}$ $H_{5}$ $OK_{}$ +$H_{2}$ $O_{}$ .
$CH_{3}$ $COOCH=CH_{2}$ + $Br_{2}$ →$CH_{3}$ $COOCH(Br)_{}$$-CH_{2}$ $Br_{}$
$CH_{2}$ $=C(CH_{3}$ $)COOCH_{3}$+$Br_{2}$ →$(Br)CH_{2}$ $-CBr(CH_{3}$ $)COOCH_{3}$.
$CH_{2}$ $=CHCOOCH=CH_{2}$ +$Br_{2}$ →$Br-CH_{2}$ $-CH(Br)COOCH(Br)CH_{2}Br$.
$C_{2}$ $H_{5}$ $COOCH_{2}$ $CH=CH_{2}$ +$H_{2}$ →$C_{2}$ $H_{5}$ $COOCH_{2}$ $-CH_{2}$ $-CH_{3}$.
$CH_{2}$ $=C(CH_{3}$ $)COOCH_{3}$ + $H_{2}$ →$CH_{3}$ $-CH(CH_{3}$ $)COOCH_{3}$ .
2$HCOOCH_{3}$+3$O_{2}$ →$4CO_{2}$ + $4H_{2}$ $O_{}$ .
2$CH_{3}$ $COOCH=CH_{2}$+ 9$O_{2}$ →$8CO_{2}$ + $6H_{2}$ $O_{}$ .
$C_{n}$$H_{2n+2-2k}$ $O_{x}$+[1,5n+(0,5(1-k-x)]$O_{2}$ →$nCO_{2}$ + $(n+1-k)H_{2}$ $O_{}$ .
