Đáp án+Giải thích các bước giải:
`a)x(y+3)=5`
Vì `x;y in ZZ=>x;(y+3) in Ư (5)={+-1;+-5}`
Ta có bảng sau:
\begin{array}{|c|c|c|}\hline \text{x}&\text{1}&\text{5}&\text{-1}&\text{-5}\\\hline \text{y+3}&\text{5}&\text{1}&\text{-5}&\text{-1}\\\hline \hline \text{x}&\text{1}&\text{5}&\text{-1}&\text{-5}\\\hline \text{y}&\text{2}&\text{-2}&\text{-8}&\text{-4}\\\hline\end{array}
Vậy cặp `(x;y)`cần tìm là:`(1;2),(5;-2),(-1;-8),(-5;-4)`
`b)(x+5)(y-1)=-6`
Vì `x;y in ZZ=>x+5;y-1 in Ư (6)={+-1;+-2;+-3;+-6}`
Ta có bảng sau:
\begin{array}{|c|c|c|}\hline \text{x+5}&\text{1}&\text{2}&\text{3}&\text{6}&\text{-1}&\text{-2}&\text{-3}&\text{-6}\\\hline \text{y-1}&\text{-6}&\text{-3}&\text{-2}&\text{-1}&\text{6}&\text{3}&\text{2}&\text{1}\\\hline \text{x}&\text{-4}&\text{-3}&\text{-2}&\text{1}&\text{-6}&\text{-7}&\text{-8}&\text{-11}\\\hline \text{y}&\text{-5}&\text{-2}&\text{-1}&\text{0}&\text{7}&\text{4}&\text{3}&\text{2}\\\hline\end{array}
Vậy cặp `(x;y)`cần tìm là:`(-4;-5),(-3;-2),(-2;-1),(1;0),(-6;7),(-7;4),(-8;3),(-11;2)`
