`d//` Để `C∈Z` thì $1$ $\vdots$ $2(x+1)$
`=>2(x+1)` là `Ư_{(1)}<=> 2(x+1)=±1`
`<=>` \(\left[ \begin{array}{l}x+1=\dfrac{1}{2}\\x+1=\dfrac{-1}{2}\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=\dfrac{-1}{2}(t/m)\\x=\dfrac{-3}{2}(t/m)\end{array} \right.\)