Đáp án:
\(\begin{array}{l}
6.\\
\frac{{{R_P}}}{{{R_e}}} = 1840\\
7.\\
\begin{array}{*{20}{l}}
{R = 2,{{318.10}^{ - 18}}m}\\
{}\\
{N = 1,{{0989.10}^{26}}}
\end{array}
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
6.\\
R = \frac{{mv}}{{|q|B}}\\
\Rightarrow \frac{{{R_P}}}{{{R_e}}} = \frac{{{m_P}}}{{{m_e}}} = 1840\\
7.\\
\begin{array}{*{20}{l}}
{R = \frac{{mv}}{{|q|B}} = \frac{{9,{{1.10}^{ - 31}}{{.8.10}^8}}}{{3,{{14.10}^{ - 4}}}} = 2,{{318.10}^{ - 18}}m}\\
{c = \pi .R = \pi .2,{{318.10}^{ - 18}} = 7,{{28.10}^{ - 18}}m}\\
{N = \frac{v}{c} = \frac{{{{8.10}^8}}}{{7,{{28.10}^{ - 18}}}} = 1,{{0989.10}^{26}}}
\end{array}
\end{array}\)
