Đáp án:
Giải thích các bước giải:
⇔ 10−x10010−x100 -1+20−x11020−x110 -1+30−x12030−x120 -1=0
⇔10−x−10010010−x−100100 +20−x−11011020−x−110110 +30−x−12012030−x−120120 =0
⇔−90−x100−90−x100 +−90−x110−90−x110 +−90−x120−90−x120 =0
⇔ (-90-x).(11001100 +11101110+ 11201120 )=0
⇒ -90-x=0
⇔ x=-90
⇔ $\frac{10-x}{100}$ -1+$\frac{20-x}{110}$ -1+$\frac{30-x}{120}$ -1=0
⇔$\frac{10-x-100}{100}$ +$\frac{20-x-110}{110}$ +$\frac{30-x-120}{120}$ =0
⇔$\frac{-90-x}{100}$ +$\frac{-90-x}{110}$ +$\frac{-90-x}{120}$ =0
⇔ (-90-x).($\frac{1}{100}$ +$\frac{1}{110}$+ $\frac{1}{120}$ )=0
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4. Mathematics_____ difficult. * a. were b. are c. is d. was
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