Đáp án:
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`a,`
`3/4 (x+1) -1/4 (x-2) = 5/8`
`-> 3/4x+3/4 - 1/4x + 1/2 = 5/8`
`-> (3/4x -1/4x) + (3/4+1/2)=5/8`
`-> (3/4 - 1/4)x + (3/4 +2/4)=5/8`
`-> 1/2x + 5/4=5/8`
`-> 1/2x=5/8-5/4`
`->1/2x=5/8 - 10/8`
`-> 1/2x = (-5)/8`
`-> x=(-5)/8÷1/2`
`->x=(-5)/4`
Vậy `x=(-5)/4`
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`b,`
`2/3 - 1/3 (x-3/2) - 1/2 (2x+1)=5`
`-> 2/3 - 1/3x + 1/2 - x - 1/2=5`
`-> ( (-1)/3x - x) + (2/3 + 1/2 - 1/2) =5`
`-> ( (-1)/3-1)x + 2/3 = 5`
`->( (-1)/3 - 3/3)x + 2/3=5`
`-> (-4)/3x +2/3=5`
`-> (-4)/3x = 5-2/3`
`-> (-4)/3x = 15/3 - 2/3`
`-> (-4)/3x = 13/3`
`->x=13/3 ÷ (-4)/3`
`->x=(-13)/4`
Vậy `x=(-13)/4`
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`c,`
`(x-3/5) (3-x)=0`
`->x-3/5=0` hoặc `3-x=0`
`->x=0+3/5` hoặc `x=3-0`
`->x=3/5` hoặc `x=3`
Vậy `x=3/5` hoặc `x=3`
