C1:
`(2x-3)(2x+3)-(2x-3)^2`
`=(4x^2-9)-(4x^2−12x+9)`
`=4x^2-9-4x^2+12x-9`
`=12x-18`
C2:
$x^2 (x+3) - 4x - 12=0$
$x^2 (x+3) - 4(x+3)=0$
$(x^2-4)(x+3)=0$
$(x-2)(x+2)(x+3)=0$
$\left[ \begin{array}{l}x-2=0\\x+2=0\\x+3=0\end{array} \right.$
$\left[ \begin{array}{l}x=2\\x=-2\\x=-3\end{array} \right.$
$\text{Vậy x ∈ {-3 ; 2 ; -2 }}$
C3:
`A = 5 -4x^2+4x`
`=-(4x^2-4x-5)`
`=-(4x^2-4x+1-6)`
`=-(4x^2-4x+1)+6`
`=-(2x-1)^2+6`
`\text{Vì}` `-(2x-1)^2 ≤ 0`
$\text{Nên}$ `-(2x-1)^2 + 6 ≤ 6`
`\text{Dấu}` `''=''` $\text{xảy ra khi}$ `2x-1=0⇔x=1/2`
$\text{Vậy}$ `Max_A=6` $\text{tại}$ `x=1/2`