Đáp án:
+$ 1 $
+$ -1$
Giải thích các bước giải:
\[\begin{array}{l}
\mathop {\lim }\limits_{x \to 1} \left( {{x^{10}} - \frac{1}{{{x^2}}} - 1} \right) = \mathop {\lim }\limits_{x \to 1} \left( {{1^{10}} - \frac{1}{{{1^2}}} - 1} \right) = 1\\
\mathop {\lim }\limits_{x \to 4} \left( {{x^2} - \frac{{16}}{{{x^2}}} + x - 20} \right) = \mathop {\lim }\limits_{x \to 4} \left( {{4^2} - \frac{{16}}{{{4^2}}} + 4 - 20} \right) = - 1
\end{array}\]