\(\Leftrightarrow x^3\left(x-y\right)-y^3\left(x-y\right)\)\(\Leftrightarrow\left(x-y\right)^2\left(x^2+xy+y^2\right)\)\(\ge0\left(\forall x;y\right)\)(tự cm nhé)
\(\dfrac{x^4+y^4}{2}\ge\dfrac{x+y}{2}.\dfrac{x^3+y^3}{2}\Leftrightarrow\dfrac{2\left(x^4+y^4\right)}{4}\ge\dfrac{(x^4+y^4)+(x^3y+xy^3)}{4}\)( luôn đúng như trên)