Đáp án:
`m_{A//1(l)}=1,518(g)`
`%m_{NO_2}=45,098%`
`%m_{N_2}=54,902%`
Giải thích các bước giải:
`n_{NO_2}=(2,24)/(22,4)=0,1(mol)`
`n_{N_2}=(5,6)/28=0,2(mol)`
`%n_{NO_2}=(0,1)/(0,1+0,2).100=33,333%`
`%n_{N_2}=(0,2)/(0,1+0,2).100=66,667%`
`=>`
`%V_{NO_2}=33,333%`
`%V_{N_2}=66,667%`
`=>1\ l\ A` gồm
`V_{NO_2}=1.33,333%=0,333(l)`
`V_{N_2}=1.66,667%=0,667(l)`
`=>`
`n_{NO_2}=(0,333)/(22,4)=5/336(l)`
`n_{N_2}=(0,667)/(22,4)=5/168(l)`
`=>`
`m_A=5/336 .46+5/168 .28=1,518(g)`
`m_{NO_2}=0,1.46=4,6(g)`
`m_A=0,1.46+5,6=10,2(g)`
`%m_{NO_2}=(4,6)/(10,2).100=45,098%`
`%m_{N_2}=(5,6)/(10,2).100=54,902%`
