` a) ` ` x(x - 3) + x - 3 = 0 `
` <=> x(x - 3) + (x - 3) = 0 `
` <=> (x - 3)(x + 1) = 0 `
` <=> ` \(\left[ \begin{array}{l}x-3=0\\x+1=0\end{array} \right.\)
` <=> ` \(\left[ \begin{array}{l}x=3\\x=-1\end{array} \right.\)
Vậy ` x = 3 ` hoặc ` x = -1 `
` b) ` ` 4x^3 - 36x = 0 `
` <=> 4x(x^2 - 9) = 0 `
` <=> 4x(x - 3)(x + 3) = 0 `
` <=> ` \(\left[ \begin{array}{l}x=0\\x-3=0\\x+3=0\end{array} \right.\)
` <=> ` \(\left[ \begin{array}{l}x=0\\x=3\\x=-3\end{array} \right.\)
Vậy ` x = 0, ` ` x = 3 ` hoặc ` x = -3 `
` c) ` ` x(x - 1) - x^2 + 2x = 5 `
` <=> x^2 - x - x^2 + 2x = 5 `
` <=> x = 5 `
Vậy ` x = 5 `
` d) ` ` x^2 - 3x + 2 + |x - 1| = 0 `
` <=> ` \(\left[ \begin{array}{l}x^2-3x+2+x-1=0\\x^2-3x+2-x+1=0\end{array} \right.\)
` <=> ` \(\left[ \begin{array}{l}x^2-2x+1=0\\x^2-4x+3=0\end{array} \right.\)
` <=> ` \(\left[ \begin{array}{l}(x-1)^2=0\\(x-1)(x-3)=0\end{array} \right.\)
` <=> ` \(\left[ \begin{array}{l}x-1=0\\x-3=0\end{array} \right.\)
` <=> ` \(\left[ \begin{array}{l}x=1\\x=3\end{array} \right.\)
Vậy ` x = 1 ` hoặc ` x = 3 `
