Đáp án + Giải thích các bước giải:
\(\begin{array}{l}
a)\\ 16x^2+24x+9 \\=(4x)^2+2.4x.3+3^2\\=(4x+3)^2\\b)\\\dfrac{x^2}{4}-3x+9\\=(\dfrac{x}{2})^2-2.\dfrac{x}{2}.3+3^2\\=(\dfrac{x}{2}-3)^2\\c)\\\dfrac{25}{x^2}-\dfrac{10}{x}+1\\=(\dfrac{5}{x})^2-2.\dfrac{5}{x}.1+1^2\\=(\dfrac{5}{x}-1)^2\\d)\\4x^4y^8+(x^2y^4)^4+4\\=[(x^2y^4)^2]^2+2.(x^2y^4)^2.2+2^2\\=[(x^2y^4)^2+2]^2\\=(x^4y^8+2)^2\\e)\\(2x-y)^2+2(2x-y)+1\\=(2x-y)^2+2(2x-y).1+1^2\\=(2x-y+1)^2\\f)\\(2x-4y)^2+4x-8y+1\\=(2x-4y)^2-2(2x-4y).1+1^2\\=(2x-4y+1)^2
\end{array}\)
