Giải thích các bước giải:
Bài 1 :
a) x + 5 = 7
<=> x = 7 - 5
<=> x = 2
b) x - ( x + 2 ) ( x - 3 ) = 4 - x^2
<=> x - ( x^2 - 3x + 2x - 6 ) = 4 - x^2
<=> x - ( x^2 - x - 6 ) = 4 - x^2
<=> x - x^2 + x + 6 = 4 - x^2
<=>x + x + 6 4
<=> 2x + 6 = 4
<=> 2x = 4 - 6
<=> 2x = - 2
<=> x = - 1
c) 4x - 3 = 2x + 2
<=>4x - 2x = 2 + 3
<=> 2x = 5
<=> x = 5/2
d) (2x - 3)^2 = 4x^2 - 8
<=> 4x^2 - 12x + 9 = 4x^2 - 8
<=> -12x + 9 = -8
<=> - 12x = -8 - 9
<=> - 12x = - 17
<=> x = 17/12
Bài 2 :
a)
<=> x^2 - 10x + 25 + x62 + 6x + 9 = 2 ( x^2 - 16 ) - 5x + 7
<=> 2x^2 - 4x + 34 = 2x^2 - 32 - 5x + 7
<=> 2x^2 0 4x + 34 = 2x^2 - 25 - 5x
<=> - 4x + 34 = - 25 - 5x
<=> - 4x + 5x = - 25 - 34
<=> x = - 59
b)
<=> ( x - 1 ) ( 3x - 6 ) ( 2x + 3 ) = 0
TH1 : x - 1 = 0
x = 1
TH2 : 3x - 6 = 0
x = 2
TH3 : 2x + 3 = 0
x = - 3/2
c)
<=> 2x^2 - 8x + 5x - 20 = 5x - x^2 - 20 + 4x
<=> 2x^2 - 8x = -x^2 + 4x
<=> 2x^2 - 8x + x^2 - 4x = 0
<=> 3x^2 - 12x = 0
<=> 3x ( x - 4 ) = 0
TH1 : 3x = 0
x = 0
TH2 : x - 4 = 0
x = 4
d)
<=> 16x^2 - 25 = 8x^2 + 4x - 10 - 5
<=> 16x^2 - 25 = 8x^2 - 6x - 5
<=> 16x^2 - 25 - 8x^2 + 6x + 5 = 0
<=> 8x^2 - 20 + 6x = 0
<=> 4x^2 - 10 + 3x = 0
<=> 4x^2 + 3x - 10 = 0
<=> 4x^2 + 8x - 5x - 10 = 0
<=> 4x ( x + 2 ) - 5 ( x + 2 ) = 0
<=> ( x + 2 ) ( 4x - 5 ) = 0
TH1 : x + 2 = 0
x = - 2
TH2 : 4x - 5 = 0
x = 5/4
e)
<=> [ 3x = 1 - 2 ( x - 3 ) ] [ 3x + 1 + 2 ( x - 3 ) ] = 0
<=> ( 3x + 1 - 2x + 6 ) ( 3x + 1 = 2x - 6 ) = 0
<=> ( x + 7 ) ( 5x - 5 ) = 0
TH1 : x + 7 = 0
x = - 7
TH2 : 5x - 5 = 0
x = 1
Nhớ cho mình trả lây hay nhất nha