Đáp án:
b) 48,75g
c) 3M
d) 120,75 g
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2}\\
b)\\
{n_{{H_2}}} = \dfrac{V}{{22,4}} = \dfrac{{16,8}}{{22,4}} = 0,75\,mol\\
{n_{Zn}} = {n_{{H_2}}} = 0,75\,mol\\
{m_{Zn}} = n \times M = 0,75 \times 65 = 48,75g\\
c)\\
{n_{{H_2}S{O_4}}} = {n_{{H_2}}} = 0,75\,mol\\
{C_M}{H_2}S{O_4} = \dfrac{n}{V} = \dfrac{{0,75}}{{0,25}} = 3M\\
d)\\
{n_{ZnS{O_4}}} = {n_{{H_2}}} = 0,75\,mol\\
{m_{ZnS{O_4}}} = n \times M = 0,75 \times 161 = 120,75g
\end{array}\)
