Em tham khảo nha :
\(\begin{array}{l}
a)\\
Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2}\\
M + 2{H_2}S{O_4} \to MS{O_4} + S{O_2} + 2{H_2}O\\
b)\\
{n_{S{O_2}}} = \dfrac{{6,72}}{{22,4}} = 0,3mol\\
{n_{{H_2}}} = \dfrac{{4,48}}{{22,4}} = 0,2mol\\
{n_{Zn}} = {n_{{H_2}}} = 0,2mol\\
{m_{Zn}} = 0,2 \times 65 = 13g\\
{m_M} = 32,05 - 13 = 19,05g\\
{n_M} = {n_{S{O_2}}} = 0,3mol\\
{M_M} = \dfrac{{19,05}}{{0,3}} = 64dvC\\
\Rightarrow M:\text{Đồng}(Cu)\\
c)\\
\% Zn = \dfrac{{13}}{{32,05}} \times 100\% = 40,56\% \\
\% Cu = 100 - 40,56 = 59,44\%
\end{array}\)