`g) (6/7 - 5/6 x) : 3/5 = 6/11 : 3/11`
`( 6/7 - 5/6 x) : 3/5 = 2`
`( 6/7 - 5/6 x) = 2 . 3/5`
`6/7 - 5/6 x = 6/5`
`5/6 x = 6/7 - 6/5`
`5/6 x =-12/35`
`x = -12/35 : 5/6`
`x = -71/175`
`h) | 3/4 x - 1/2| . 4 = 3`
` | 3/4 x - 1/2| = 3 :4`
`| 3/4 x - 1/2| = 3/4`
⇒ `3/4 x - 1/2 = 3/4` hoặc `3/4 x - 1/2 = -3/4`
`3/4 x = 3/4 + 1/2` hoặc `3/4 x = -3/4 + 1/2`
`3/4 x = 5/4` hoặc `3/4 x = -1/4`
`x = 5/4 : 3/4` hoặc `x = -1/4 : 3/4`
`x = 5/3` hoặc `x = -1/3`
Vậy `x∈ {5/3 ; -1/3}`
