$nH2=8,96/22,4=0,4 mol$
$pthh:$
$Zn + 2HCl → ZnCl2 + H2$
$theo$ $pt:$
$nH2=nZn=0,4mol$
$⇒mZn=0,4..65=26g$
$⇒\%mFe=$$\frac{26.100}{30}=86,67\%$
$⇒\%mCu=100\%-86,67\%=13,33\%$
$c/$
$theo$ $pt:$
$nZnCL2=nZn=0,4mol$
$⇒mZnCl2=0,4.136=54,4g$
$d/$
$nCuO=50/50=0,625mol$
$pthh:$
$CuO + H2 → Cu + H2O$
$Ta$ $có :$
$n_{H_{2}pư}=a (mol)$
$⇒80=\frac{100a}{0,4}$
$⇔x=80.0,4÷100=0,32mol$
$Theo$ $pt :$
$nCu=n_{H_{2}pư}=0,32mol$
$⇒mCu=0,32.64=20,48(g)$
$⇒nCu=n_{CuO_{dư}}=0,32mol$
$⇒n_{CuO_{dư}}=0,625-0,32=0,305mol$
$⇒m_{CuO_{dư}}=0,305.80=24,4(g)$
$⇒m_{rắn}=24,4+20,48=44,88(g)$
