` a) ` ` 2x(x - 1) = x^2 - 2x + 1 `
` => 2x(x - 1) = (x - 1)^2 `
` => 2x = x - 1 ` hoặc ` x - 1 = 0 `
` => x - 2x = 1 ` ` => x = 1 `
` => x = -1 `
Vậy ` x = -1 ` hoặc ` x = 1 `
` b) ` ` \frac{3x - 1}{4} - x/2 = \frac{x + 1}{6} `
` => \frac{3x - 1}{4} - x/2 - \frac{x + 1}{6} = 0 `
` => \frac{9x - 3 - 6x - 2x - 2}{12} = 0 `
` => \frac{x - 5}{12} = 0 `
` => x - 5 = 0 `
` => x = 5 `
Vậy ` x = 5 `
