Đáp án:
\(\left\{ \begin{array}{l}
x = - 1\\
y = \dfrac{1}{2}
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
\left\{ \begin{array}{l}
4xy - 2x + 2y - 1 = 4xy - x + 4y - 1\\
6xy - x + 6y - 1 = 6xy - 3x + 4y - 2
\end{array} \right.\\
\to \left\{ \begin{array}{l}
x + 2y = 0\\
2x + 2y = - 1
\end{array} \right.\\
\to \left\{ \begin{array}{l}
- x = 1\\
x + 2y = 0
\end{array} \right.\\
\to \left\{ \begin{array}{l}
x = - 1\\
y = \dfrac{1}{2}
\end{array} \right.
\end{array}\)
