a) $\dfrac{a}{5}=\dfrac{b}{2}=\dfrac{3a+4b}{3.5+4.2}=\dfrac{46}{23}=2$
$\Rightarrow a=2.5=10$
$b=2.2=4$
b) $\dfrac{a}{5}=\dfrac{b}{3}=\dfrac{3a+2b}{3.5+2.3}=\dfrac{84}{21}=4$
$\Rightarrow a=4.5=20$
$b=4.3=12$
c) $\dfrac{a}{5}=\dfrac{b}{-2}=\dfrac{a-b}{5-(-2)}=\dfrac{-21}{7}=-3$
$\Rightarrow a=-3.5=-15$
$b=-3.(-2)=6$