Em tham khảo nha:
\(\begin{array}{l}
6)\\
a)\,CuO + 2HCl \to CuC{l_2} + {H_2}O\\
b)\,ZnO + {H_2}S{O_4} \to ZnS{O_4} + {H_2}O\\
c)\,N{a_2}O + 2HCl \to 2NaCl + {H_2}O\\
d)\,FeO + {H_2}S{O_4} \to FeS{O_4} + {H_2}O\\
e)\,A{l_2}{O_3} + 3{H_2}S{O_4} \to A{l_2}{(S{O_4})_3} + 3{H_2}O\\
f)\,{K_2}O + 2HCl \to 2KCl + {H_2}O\\
g)\,CuO + {H_2}S{O_4} \to CuS{O_4} + {H_2}O\\
h)\,CaO + {H_2}O \to Ca{(OH)_2}\\
i)\,N{a_2}O + {H_2}O \to 2NaOH\\
j){K_2}O + {H_2}O \to 2KOH\\
7)\\
a)\\
(1)\,N{a_2}O + {H_2}O \to 2NaOH\\
(2)\,2NaOH + {H_2}S{O_4} \to N{a_2}S{O_4} + 2{H_2}O\\
b)\\
(1)\,2Ca + {O_2} \xrightarrow{t^0} 2CaO\\
(2)\,CaO + {H_2}O \to Ca{(OH)_2}\\
(3)\,Ca{(OH)_2} + 2HCl \to CaC{l_2} + 2{H_2}O\\
8)\\
a)\\
FeO + 2HCl \to FeC{l_2} + {H_2}O\\
FeC{l_2}:\\
b)\\
{n_{FeO}} = \dfrac{{14,4}}{{72}} = 0,2\,mol\\
{n_{FeC{l_2}}} = {n_{FeO}} = 0,2\,mol\\
{m_{FeC{l_2}}} = 0,2 \times 127 = 25,4g\\
c)\\
{n_{HCl}} = 2{n_{FeO}} = 0,4\,mol\\
{C_M}HCl = \dfrac{{0,4}}{{0,2}} = 2M
\end{array}\)
