h) Ta có:\(-\left(\dfrac{1}{2}\right)^2\).13\(\dfrac{9}{11}\) - 25%.6\(\dfrac{2}{11}\)
= \(-\dfrac{2}{2}\).\(\dfrac{152}{11}\) - \(\dfrac{25}{100}\).\(\dfrac{68}{11}\)
= -1 .\(\dfrac{152}{11}\) - \(\dfrac{1}{4}\) . \(\dfrac{68}{11}\)
= \(\dfrac{-152}{11}\) - 1.\(\dfrac{17}{11}\)
= \(\dfrac{-152-17}{11}\)
= \(\dfrac{-152+\left(-17\right)}{11}\)
= \(\dfrac{-169}{11}\)
i) Ta có: 57% + 1\(\dfrac{2}{15}\): \(\dfrac{68}{25}\) - 2,82
= \(\dfrac{57}{100}\) + \(\dfrac{17}{15}:\dfrac{68}{25}\) - \(\dfrac{282}{100}\)
= \(\dfrac{17}{15}.\dfrac{68}{25}\)+ \(\dfrac{57}{100}\)-\(\dfrac{282}{100}\)
= \(\dfrac{1156}{375}\) + \(\dfrac{57+\left(-282\right)}{100}\)
= \(\dfrac{1156}{375}\) + \(\dfrac{-225}{100}\)
= \(\dfrac{1156}{375}\) + \(\dfrac{-9}{4}\)
= \(\dfrac{4624}{1500}\) + \(\dfrac{-3375}{1500}\)
= \(\dfrac{1249}{1500}\)
Mk nghĩ là như z đó.
Chúc bn học tốt!!!
