a) $\widehat{AOD}+\widehat{AOC}=180^o$ (kề bù)
mà $\widehat{AOD}=110^o$
$⇒\widehat{AOC}=180^o-110^o=70^o$
Vì $AB∩CD≡O$
$⇒\widehat{AOC}=\widehat{BOD}=70^o$ (đối đỉnh)
$⇒\widehat{AOD}=\widehat{BOC}=110^o$ (đối đỉnh)
b) $\widehat{AOC}+\widehat{BOD}=140^o$
mà $\widehat{AOC}=\widehat{BOD}$
$⇒2.\widehat{AOC}=140^o$
$⇒\widehat{AOC}=\widehat{BOD}=140^o:2=70^o$
Vì $\widehat{AOC},\widehat{AOD}$ là hai góc kề bù
$⇒\widehat{AOC}+\widehat{BOD}=180^o$
mà $\widehat{AOC}=70^o$
$⇒\widehat{AOD}=\widehat{BOC}=180^o-70^o=110^o$ (đối đỉnh)